document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=688669>Question 688669</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the area of two squares is 89 square centimeters. The length of a side of the larger square is 3 cm more than the length of a side of the smaller square. find the dimensions of each square.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #425679 by </B><A HREF=/tutors/aboutme.mpl?userid=sachi><B>sachi(548)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sachi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sachi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=425679\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The length of a side of the larger square is 3 cm more than the length of a side of the smaller square.<BR>\n" );
document.write( "let the side of the smaller square is a cm then larger square has sides a+3 cm\r<BR>\n" );
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document.write( "The sum of the area of two squares is 89 square centimeters. <BR>\n" );
document.write( "so a^2+(a+3)^2=89<BR>\n" );
document.write( "or a^2+a^2+9+6a=89<BR>\n" );
document.write( "or 2a^2+6a-80=0<BR>\n" );
document.write( "or a^2+3a-40=0<BR>\n" );
document.write( "or a^2+8a-5a-40=0<BR>\n" );
document.write( "or a(a+8)-5(a+8)=0<BR>\n" );
document.write( "or (a+8)(a-5)=0<BR>\n" );
document.write( "or a+8=0=> a=-8 rejected for -ve value<BR>\n" );
document.write( "then (a-5=0 =>a=5 the side of the smaller square<BR>\n" );
document.write( "& the sides of the larger square is 3+5=8 cms<BR>\n" );
document.write( "ans<BR>\n" );
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