document.write( "Question 688516: For the equation of the ellipse, find the coordinates of the CENTER, FOCI, and VERTICES. THEN GRAPH.
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document.write( "4x^2+9y^2-8x+36y+4=0\r
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document.write( "Please help I've been doing this homework for an hour. \n" );
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Algebra.Com's Answer #425673 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! For the equation of the ellipse, find the coordinates of the CENTER, FOCI, and VERTICES. THEN GRAPH. \n" ); document.write( "4x^2+9y^2-8x+36y+4=0 \n" ); document.write( "complete the square \n" ); document.write( "4x^2-8x+9y^2+36y+4=0 \n" ); document.write( "4(x^2-2x+1)+9(y^2+4y+4)=-4+4+36 \n" ); document.write( "4(x-1)^2+9(y+2)^2=36 \n" ); document.write( "(x-1)^2/9+(y+2)^2/4=1 \n" ); document.write( "This is an equation of an ellipse with horizontal major axis. \n" ); document.write( "Its standard form: \n" ); document.write( "For given ellipse: \n" ); document.write( "center:(1,-2) \n" ); document.write( "a^2=9 \n" ); document.write( "a=√9=3 \n" ); document.write( "vertices: (1±a,-2)=(1±3,-2)=(4,-2) and (-2,-2) \n" ); document.write( "b^2=4 \n" ); document.write( "b=√4=2 \n" ); document.write( "c^2=a^2-b^2=9-4=5 \n" ); document.write( "c=√5≈2.24 \n" ); document.write( "Foci:(1±c,-2)=(1±2.24,-2)=(3.24,-2) and (-1.24,-2) \n" ); document.write( "see graph below: \n" ); document.write( "y=±(4-(4(x-1)^2/9))^.5-2 \n" ); document.write( " |