document.write( "Question 688586: Sketch the graph of the parabola, determine the vertex, focus, axis and the directrix:
\n" ); document.write( "y^2=12x \n" ); document.write( "

Algebra.Com's Answer #425671 by lwsshak3(11628) $\"\"$ $\"About$

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Sketch the graph of the parabola, determine the vertex, focus, axis and the directrix:
\n" ); document.write( "y^2=12x
\n" ); document.write( "**
\n" ); document.write( "This is an equation of a parabola that opens rightwards.
\n" ); document.write( "Its standard form: (y-k)^2=4p(x-h), (h,k)=(x,y) coordinates of the vertex
\n" ); document.write( "For given equation:y^2=12x
\n" ); document.write( "vertex:(0,0)
\n" ); document.write( "axis of symmetry: y=0 or x-axis
\n" ); document.write( "4p=12
\n" ); document.write( "p=3
\n" ); document.write( "focus:(3,0) (p-distance to the right of the vertex on the axis of symmetry)
\n" ); document.write( "directrix: x=-3 (p-distance to the left of the vertex on the axis of symmetry)
\n" ); document.write( "see graph below:
\n" ); document.write( " $\"+graph%28+300%2C+300%2C+-10%2C+10%2C+-10%2C+10%2C+%2812x%29%5E.5%2C-%2812x%29%5E.5%29+\"$ \n" ); document.write( "

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