document.write( "Question 688624: (y+2)^2=-8(x-1) \n" ); document.write( "
Algebra.Com's Answer #425670 by lwsshak3(11628)\"\" \"About 
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(y+2)^2=-8(x-1)
\n" ); document.write( "This is an equation of a parabola that opens leftwards.
\n" ); document.write( "Its standard form: (y-k)^2=-4p(x-h), (h,k)=(x,y) coordinates of the vertex.
\n" ); document.write( "For given equation:
\n" ); document.write( "vertex:(1,-2)
\n" ); document.write( "axis of symmetry: y=-2
\n" ); document.write( "4p=8
\n" ); document.write( "p=2
\n" ); document.write( "focus:(-1,-2) (p-distance to the left of the vertex on the xis of symmetry)
\n" ); document.write( "directrix:x=3 (p-distance to the right of the vertex on the xis of symmetry)
\n" ); document.write( "
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