document.write( "Question 61839: in a class of 40 student, 80% are business majors. Of the 24 students who passed the midterm examination, 75% are business majors. What percentage of students in the class who are not business majors passed the examination? \n" ); document.write( "
Algebra.Com's Answer #42567 by still_happy2006(3)![]() ![]() ![]() You can put this solution on YOUR website! first we must figure out how many students are business majors. We do this by multiplying:\r \n" ); document.write( "\n" ); document.write( "40 (students) x .80 (percentage of business majors) = 32 students are business majors\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subtracting we can figure out how many are not business majors\r \n" ); document.write( "\n" ); document.write( "40 students - 32 business majors = 8 non- business majors\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now we move onto the exam\r \n" ); document.write( "\n" ); document.write( "to figure how many business majors that passed the exam we multiply again:\r \n" ); document.write( "\n" ); document.write( "24 passed exam x .75 percentage of business majors = 18 business major students passed the exam\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subracting we figure out how many non-business majors passed\r \n" ); document.write( "\n" ); document.write( "24 passed exam - 18 business majors who passed = 6 non-business majors who passed the exam\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now for the last part:\r \n" ); document.write( "\n" ); document.write( "To figure out what percentage of students in the class who are not business majors passed the exam we divide:\r \n" ); document.write( "\n" ); document.write( "6 non-business majors who passed the exam divided by 8 non-business major students in the class = .75 or otherwise known as 75% \n" ); document.write( " |