document.write( "Question 688269: a front is provisioned for 75 days . after 25 days a reinforcement of 500 men arrives and the food the lasts only 40 days. how many men were in the fort? \n" ); document.write( "
Algebra.Com's Answer #425641 by ankor@dixie-net.com(22740)\"\" \"About 
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a front is provisioned for 75 days .
\n" ); document.write( " after 25 days a reinforcement of 500 men arrives and the food the lasts only 40 days. how many men were in the fort?
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\n" ); document.write( "I assume they mean it will last 40 more days after the 25 days, a total of 65 days
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\n" ); document.write( "Let m = original number of men
\n" ); document.write( "then a total of 75m man-days of provisions available
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\n" ); document.write( "75m = 25m + 40(m+500)
\n" ); document.write( "75m = 25m + 40m + 20000
\n" ); document.write( "75m = 65m + 20000
\n" ); document.write( "75m - 65m = 20000
\n" ); document.write( "10m = 20000
\n" ); document.write( "m = 2000 men originally in the fort
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\n" ); document.write( "See if this checks out:
\n" ); document.write( " 2000*75 = 150000 man-days of provisions available
\n" ); document.write( " 2000*25 = 50000 used in the 1st 25 days
\n" ); document.write( " 2500*40 = 100000 using the last 40 days
\n" ); document.write( "total comes out right\r
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