document.write( "Question 688467: When the speed of a train is increased by 10 mph, it can cover a 300 mile route in one hour less time. What is the original speed of the train? \n" ); document.write( "
Algebra.Com's Answer #425638 by ankor@dixie-net.com(22740)\"\" \"About 
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When the speed of a train is increased by 10 mph, it can cover a 300 mile route in one hour less time.
\n" ); document.write( " What is the original speed of the train?
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\n" ); document.write( "Let s = the original speed of the train
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\n" ); document.write( "Write a time equation, time = dist/speed
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\n" ); document.write( "Original time - faster time = 1 hr
\n" ); document.write( "\"300%2Fs\" - \"300%2F%28%28s%2B10%29%29\" = 1
\n" ); document.write( "Multiply by s(s+10), this clears the denominators, resulting in:
\n" ); document.write( "300(s+10) - 300s = s(s+10)
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\n" ); document.write( "300s + 3000 - 300s = s^2 + 10s
\n" ); document.write( "A quadratic equation
\n" ); document.write( "0 = s^2 + 10s - 3000
\n" ); document.write( "This factors to
\n" ); document.write( "(s+60(s-50) = 0
\n" ); document.write( "the positive solution is what we want here
\n" ); document.write( "s = 50 mph is the original speed
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\n" ); document.write( "Confirm this find the time of each scenario
\n" ); document.write( "300/50 = 6 hrs
\n" ); document.write( "300/60 = 5 hrs, 1 hr less
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