document.write( "Question 688467: When the speed of a train is increased by 10 mph, it can cover a 300 mile route in one hour less time. What is the original speed of the train? \n" ); document.write( "
Algebra.Com's Answer #425638 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! When the speed of a train is increased by 10 mph, it can cover a 300 mile route in one hour less time. \n" ); document.write( " What is the original speed of the train? \n" ); document.write( ": \n" ); document.write( "Let s = the original speed of the train \n" ); document.write( ": \n" ); document.write( "Write a time equation, time = dist/speed \n" ); document.write( ": \n" ); document.write( "Original time - faster time = 1 hr \n" ); document.write( " \n" ); document.write( "Multiply by s(s+10), this clears the denominators, resulting in: \n" ); document.write( "300(s+10) - 300s = s(s+10) \n" ); document.write( ": \n" ); document.write( "300s + 3000 - 300s = s^2 + 10s \n" ); document.write( "A quadratic equation \n" ); document.write( "0 = s^2 + 10s - 3000 \n" ); document.write( "This factors to \n" ); document.write( "(s+60(s-50) = 0 \n" ); document.write( "the positive solution is what we want here \n" ); document.write( "s = 50 mph is the original speed \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Confirm this find the time of each scenario \n" ); document.write( "300/50 = 6 hrs \n" ); document.write( "300/60 = 5 hrs, 1 hr less \n" ); document.write( " |