document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=688446>Question 688446</A>: <I><SPAN STYLE=\"word-break: break-all;\"> .\r<BR>\n" );
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document.write( "One pump can drain a pool in 12 minutes. When a second pump is also used, the pool only takes 3 minutes to drain. How long would it take the second pump to drain the pool if it were the only pump in use? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #425602 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=425602\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/12 + 1/t = 1/3\r<BR>\n" );
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document.write( "t/(12t) + 12/(12t) = 1/3\r<BR>\n" );
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document.write( "(t + 12)/(12t) = 1/3\r<BR>\n" );
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document.write( "3(t + 12) = 12t\r<BR>\n" );
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document.write( "3t + 36 = 12t\r<BR>\n" );
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document.write( "36 = 12t - 3t\r<BR>\n" );
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document.write( "36 = 9t\r<BR>\n" );
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document.write( "t = 36/9\r<BR>\n" );
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document.write( "t = 4\r<BR>\n" );
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document.write( "So if the second pump is only used, it will take 4 minutes. </SPAN>\n" );
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