document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=61778>Question 61778</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0395676088/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> 4 + 3 |5n + 1| = 13\r<BR>\n" );
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document.write( "and \r<BR>\n" );
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document.write( "5 - 4 |2-3t| = 21 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #42560 by </B><A HREF=/tutors/aboutme.mpl?userid=brandonpark2889><B>brandonpark2889(31)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=brandonpark2889><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=42560\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4 + 3 |5n + 1| = 13\r<BR>\n" );
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document.write( "and \r<BR>\n" );
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document.write( "5 - 4 |2-3t| = 21\r<BR>\n" );
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document.write( "2 problems?\r<BR>\n" );
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document.write( "Ok. First one: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+4%2B3+%7C5n%2B1%7C=13. ALIGN=MIDDLE  ALT=\"+4%2B3+%7C5n%2B1%7C=13.\"   DISABLED_style= \"max-width:90%; height:auto;\" > First, Always do the distributive prop ( if you don't know: a(b+c) = ab+ac). This case, 3 is the a. Always, multiply first. 3 x 5n = 15n. 3 x 1= 3. so it would be 4 + 15n + 3= 13. Now, add 4 and 3, which equals 7. After this, subtract 7 on each side: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+15m+%2B+7+-+7+=+13+-+7+ ALIGN=MIDDLE  ALT=\"+15m+%2B+7+-+7+=+13+-+7+\"   DISABLED_style= \"max-width:90%; height:auto;\" >. What is left is 15m=6. Now, divide 15 on each side: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=15m%2F15+=+6%2F15 ALIGN=MIDDLE  ALT=\"15m%2F15+=+6%2F15\"   DISABLED_style= \"max-width:90%; height:auto;\" >. Cancel out 15 on the first side, and 6/15 would be simplified to 2/5. m is 2/5.<BR>\n" );
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document.write( "Second Problem: Same thing. Now, NEGATIVE 4 would be the a. Multiply -4 inside the absolute value, 2 and -3t. So, -4 x 2 is -8. -4 x -3t= 12t. So, what's left is 5 + -8 + 12t=21. 5-8 is -3. ADD 3 on each side: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+-3+%2B+3+%2B+12t=+21+%2B+3 ALIGN=MIDDLE  ALT=\"+-3+%2B+3+%2B+12t=+21+%2B+3\"   DISABLED_style= \"max-width:90%; height:auto;\" > simplify: what is left is 12t=24. Divide 12 on each side: <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=12t%2F12=24%2F12 ALIGN=MIDDLE  ALT=\"12t%2F12=24%2F12\"   DISABLED_style= \"max-width:90%; height:auto;\" >. 24/12 is 2. So, t=2.\r<BR>\n" );
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document.write( "I like math, period. </SPAN>\n" );
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