document.write( "Question 688308: A company offers a starting salary of 35,000 with raises of $2,500 per year.Find the total salary over a ten-year period. \n" ); document.write( "
Algebra.Com's Answer #425584 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! 35,000 THE FIRST YEAR \n" ); document.write( "35,000+2,500=37,500 SECOND YEAR \n" ); document.write( "37,500+2,500=40,000 THIRD YEAR \n" ); document.write( "40,000+2,500=42,500 FORTH YEAR \n" ); document.write( "42,500+2,500=45,000 FIFTH YEAR \n" ); document.write( "45,000+2,500=47,500 SIXTH YEAR \n" ); document.write( "47,500+2,500=50,000 SEVENTH YEAR \n" ); document.write( "50,000+2,500=52,500 EIGHTH YEAR \n" ); document.write( "52,500+2.500=55,000 NINTH YEAR \n" ); document.write( "55,000+2,500=57,500 TENTH YEAR. \n" ); document.write( " |