document.write( "Question 688173: If the length of a rectangle is 2cm. longer than the width, and the rectangle's diagonal is the square root of 11 cm. Find the width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #425534 by stanbon(75887)\"\" \"About 
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If the length of a rectangle is 2cm. longer than the width, and the rectangle's diagonal is the square root of 11 cm. Find the width of the rectangle.
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\n" ); document.write( "Let the width be \"w\".
\n" ); document.write( "Then the length is \"w+2\".
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\n" ); document.write( "Use Pythagoras
\n" ); document.write( "w^2 + (w+2)^2 = (sqrt(11))^2
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\n" ); document.write( "w^2 + w^2 + 4w + 4 = 11
\n" ); document.write( "2w^2 + 4w - 7 = 0
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\n" ); document.write( "w = [-4 +- sqrt(16 - 4*2*-7)]/4
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\n" ); document.write( "w = [-4+- sqrt(72)]/4
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\n" ); document.write( "w = [-4 +-6sqrt(2)]/4
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\n" ); document.write( "Positive solution:
\n" ); document.write( "w = [-4 + 6sqrt(2)]
\n" ); document.write( "width = 1.12 cm
\n" ); document.write( "length = 3.12 cm
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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