document.write( "Question 688173: If the length of a rectangle is 2cm. longer than the width, and the rectangle's diagonal is the square root of 11 cm. Find the width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #425534 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! If the length of a rectangle is 2cm. longer than the width, and the rectangle's diagonal is the square root of 11 cm. Find the width of the rectangle. \n" ); document.write( "---- \n" ); document.write( "Let the width be \"w\". \n" ); document.write( "Then the length is \"w+2\". \n" ); document.write( "--- \n" ); document.write( "Use Pythagoras \n" ); document.write( "w^2 + (w+2)^2 = (sqrt(11))^2 \n" ); document.write( "---- \n" ); document.write( "w^2 + w^2 + 4w + 4 = 11 \n" ); document.write( "2w^2 + 4w - 7 = 0 \n" ); document.write( "---- \n" ); document.write( "w = [-4 +- sqrt(16 - 4*2*-7)]/4 \n" ); document.write( "---- \n" ); document.write( "w = [-4+- sqrt(72)]/4 \n" ); document.write( "---- \n" ); document.write( "w = [-4 +-6sqrt(2)]/4 \n" ); document.write( "---- \n" ); document.write( "Positive solution: \n" ); document.write( "w = [-4 + 6sqrt(2)] \n" ); document.write( "width = 1.12 cm \n" ); document.write( "length = 3.12 cm \n" ); document.write( "--------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================ \n" ); document.write( " |