document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=688156>Question 688156</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help I am in desperate need. I just do not understand these.\r<BR>\n" );
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document.write( "Two angles are supplementary. One angle is 4 degrees less than three times the other. Find the measurement of the angles. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #425530 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=425530\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two angles are supplementary. One angle is 4 degrees less than three times the other. Find the measurement of the angles.<BR>\n" );
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document.write( "Call the angles A & B<BR>\n" );
document.write( "A + B = 180 degs<BR>\n" );
document.write( "A = 3B - 4<BR>\n" );
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document.write( "Solve for A & B<BR>\n" );
document.write( "Sub for A in the 1st eqn<BR>\n" );
document.write( "(3B-4) + B = 180<BR>\n" );
document.write( "4B = 184<BR>\n" );
document.write( "B = 46 degs<BR>\n" );
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document.write( "A = 180 - B<BR>\n" );
document.write( "A = 134 degs<BR>\n" );
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