document.write( "Question 687572: Solve the equation \"+log%28+2x+%29+\" = 1 + \"+log%282%29+\" (x+112) \n" ); document.write( "
Algebra.Com's Answer #425488 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
log2(x) + 1 = log2(x+112)
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\n" ); document.write( "log2(x+112) - log2(x) = 1
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\n" ); document.write( "log2[(x+112)/x] = 1
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\n" ); document.write( "(x+112)/x = 2
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\n" ); document.write( "x + 112 = 2x
\n" ); document.write( "x = 112
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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