document.write( "Question 688046: a chemist has 40 grams of 25% sulfuric acid solution. how much pure sulfuric acid must she add to get a solution which is 30% sulfuric acid. \n" ); document.write( "
Algebra.Com's Answer #425482 by stanbon(75887)\"\" \"About 
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a chemist has 40 grams of 25% sulfuric acid solution. how much pure sulfuric acid must she add to get a solution which is 30% sulfuric acid.
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\n" ); document.write( "Equation:
\n" ); document.write( "acid + acid = acid
\n" ); document.write( "0.25*40 + 1*x = 0.30(40+x)
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\n" ); document.write( "Multiply thru by 100 to get:
\n" ); document.write( "25*40 + 100x = 30*40 + 30x
\n" ); document.write( "70x = 5*40
\n" ); document.write( "x = 200/70
\n" ); document.write( "x = 2.857 grams (amt. of pure acid to add)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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