document.write( "Question 688046: a chemist has 40 grams of 25% sulfuric acid solution. how much pure sulfuric acid must she add to get a solution which is 30% sulfuric acid. \n" ); document.write( "
Algebra.Com's Answer #425482 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! a chemist has 40 grams of 25% sulfuric acid solution. how much pure sulfuric acid must she add to get a solution which is 30% sulfuric acid. \n" ); document.write( "------- \n" ); document.write( "Equation: \n" ); document.write( "acid + acid = acid \n" ); document.write( "0.25*40 + 1*x = 0.30(40+x) \n" ); document.write( "------ \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "25*40 + 100x = 30*40 + 30x \n" ); document.write( "70x = 5*40 \n" ); document.write( "x = 200/70 \n" ); document.write( "x = 2.857 grams (amt. of pure acid to add) \n" ); document.write( "==================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================== \n" ); document.write( " |