document.write( "Question 61819: 5 School children, including L & M, will be seated in a row of 5 seats. In how many ways can this be done id L & M must NOT sit together?
\n" ); document.write( "I tried 5! (# of ways 5 can sit together) - 4! (if L & M did sit together). Please help.
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Algebra.Com's Answer #42546 by stanbon(75887)\"\" \"About 
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5 School children, including L & M, will be seated in a row of 5 seats. In how many ways can this be done id L & M must NOT sit together?
\n" ); document.write( "I tried 5! (# of ways 5 can sit together) - 4! (if L & M did sit together). Please help.
\n" ); document.write( "---------
\n" ); document.write( "5! is the number of possible arrangements.
\n" ); document.write( "There are 4 ways L and M could sit together.
\n" ); document.write( "For each of those placements there are 3! ways
\n" ); document.write( "the remaining children could be arranged.
\n" ); document.write( "Final Answer: 5!-(4*3!)=96
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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