document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=687981>Question 687981</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Imaginary numbers\r<BR>\n" );
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document.write( "i to the 37 power </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #425442 by </B><A HREF=/tutors/aboutme.mpl?userid=josh_jordan><B>josh_jordan(263)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josh_jordan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=josh_jordan><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=425442\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Take the power of i and divide by 4.  In your case, i is raised to the 37th power.  Divide 37 by 4, which is 9 with a remainder of 1.  The remainder now goes above the i.  So, i to the first power, is i.  \r<BR>\n" );
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document.write( "So, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=i%5E37 ALIGN=MIDDLE  ALT=\"i%5E37\"   DISABLED_style= \"max-width:90%; height:auto;\" > = i </SPAN>\n" );
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