document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=687953>Question 687953</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (2x+1)(x+5)=-3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #425436 by </B><A HREF=/tutors/aboutme.mpl?userid=josh_jordan><B>josh_jordan(263)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josh_jordan><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=josh_jordan><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=425436\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The first step in solving for x in this equation, is to expand the factoring on the left side of the equation:\r<BR>\n" );
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document.write( "(2x + 1)(x + 5) =\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%2Ax+%2B+2x%2A5+%2B+1x+%2B+1%2A5 ALIGN=MIDDLE  ALT=\"2x%2Ax+%2B+2x%2A5+%2B+1x+%2B+1%2A5\"   DISABLED_style= \"max-width:90%; height:auto;\" > =\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%5E2+%2B+10x+%2B+1x+%2B+5 ALIGN=MIDDLE  ALT=\"2x%5E2+%2B+10x+%2B+1x+%2B+5\"   DISABLED_style= \"max-width:90%; height:auto;\" > =\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%5E2+%2B+11x+%2B+5 ALIGN=MIDDLE  ALT=\"2x%5E2+%2B+11x+%2B+5\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Next we want to set this equation equal to 0.  To do this, add 3 to both sides, giving us\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2x%5E2+%2B+11x+%2B+8+=+0 ALIGN=MIDDLE  ALT=\"2x%5E2+%2B+11x+%2B+8+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Now, we have a quadratic equation.  Because this equation cannot be factored, we will use the quadratic formula to solve for x.\r<BR>\n" );
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document.write( "The quadratic formula:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ ALIGN=MIDDLE  ALT=\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "In our equation, a = 2, b = 11, and c = 8.  We will plug these numbers into the quadratic formula:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-11+%2B-+sqrt%2811%5E2+-+4%282%29%288%29%29%29%2F%282%282%29%29 ALIGN=MIDDLE  ALT=\"%28-11+%2B-+sqrt%2811%5E2+-+4%282%29%288%29%29%29%2F%282%282%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > =\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-11+%2B-+sqrt%28121+-+64%29%29%2F4 ALIGN=MIDDLE  ALT=\"%28-11+%2B-+sqrt%28121+-+64%29%29%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" > =\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-11+%2B-+sqrt%2857%29%29%2F4 ALIGN=MIDDLE  ALT=\"%28-11+%2B-+sqrt%2857%29%29%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Final Answer:\r<BR>\n" );
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document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-11+%2B+sqrt%2857%29%29%2F4 ALIGN=MIDDLE  ALT=\"%28-11+%2B+sqrt%2857%29%29%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" >,<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-11+-+sqrt%2857%29%29%2F4 ALIGN=MIDDLE  ALT=\"%28-11+-+sqrt%2857%29%29%2F4\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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