document.write( "Question 687910: The width of a rectangle is 5 feet less than its length. If the perimeter is 22 feet, what is the width?
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Algebra.Com's Answer #425428 by checkley79(3341)\"\" \"About 
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P=2L+2W
\n" ); document.write( "W=L-5
\n" ); document.write( "22=2L+2(L-5)
\n" ); document.write( "22=2L+2L-10
\n" ); document.write( "4L=22+10
\n" ); document.write( "4L32
\n" ); document.write( "L=32/4
\n" ); document.write( "L=8 ANS. FOR THE LWNGTH.
\n" ); document.write( "W=8-5=3 ANS. FOR THE WIDTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "22=-2*8+2*3
\n" ); document.write( "22=16+6
\n" ); document.write( "22=22\r
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