document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=687593>Question 687593</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Using a right triangle to write the expression as an algebraic expression. Assume that x is positive and in the domain of the given inverse trigonometric function. The problem I have to solve is sin[tan-1x] *Not negative one, the inverse of tan. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #425412 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=425412\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Using a right triangle to write the expression as an algebraic expression. Assume that x is positive and in the domain of the given inverse trigonometric function. The problem I have to solve is sin[tan-1x] *Not negative one, the inverse of tan.<BR>\n" );
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document.write( "Let theta be tan^-1(x)<BR>\n" );
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document.write( "Since tan(theta) = x/1, x = opp and 1 = base<BR>\n" );
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document.write( "Find hypotenuse: h = sqrt[x^2 + 1^2]<BR>\n" );
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document.write( "Therefore sin(theta) = opp/hypot = x/sqrt(x^2+1)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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