document.write( "Question 61805: Can you help me with this problem please! : The length of a rectangle is 4 cm less that three times its width. If the length is increased by 8 cm and the width is decreased by 2 cm, the perimeter will be 100 cm. Find the dimensions of the original rectangle. \n" ); document.write( "
Algebra.Com's Answer #42537 by Nate(3500)\"\" \"About 
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Original:
\n" ); document.write( "width = w
\n" ); document.write( "length = 3w - 4
\n" ); document.write( "Tampered:
\n" ); document.write( "width = w - 2
\n" ); document.write( "length = 3w + 4
\n" ); document.write( "2l + 2w = perimeter
\n" ); document.write( "2(3w + 4) + 2(w - 2) = 100
\n" ); document.write( "6w + 8 + 2w - 4 = 100
\n" ); document.write( "8w = 96
\n" ); document.write( "w = 12
\n" ); document.write( "width = 12 - 2 = 10cm
\n" ); document.write( "length = 3(12) + 4 = 36 + 4 = 40cm
\n" ); document.write( "Original:
\n" ); document.write( "width = w = 12cm
\n" ); document.write( "length = 3(12) - 4 = 36 - 4 = 32cm \n" ); document.write( "
\n" );