document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=687865>Question 687865</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the base of an isoceles triangle is 10cm and one of its sides is 8cm find the area of the triangle.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #425367 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=425367\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the base of an isoceles triangle is 10cm and one of its sides is 8cm find the area of the triangle.<BR>\n" );
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document.write( "Draw an isoceles triangle.<BR>\n" );
document.write( "Label the base \"10\".<BR>\n" );
document.write( "Label one of the sides 8<BR>\n" );
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document.write( "Label the other side 8 because the sides are equal.<BR>\n" );
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document.write( "Draw an altitude down from the vertex to the base.<BR>\n" );
document.write( "It is a perpendicaular-bisector of the base.<BR>\n" );
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document.write( "Each section of the base is now \"5\".<BR>\n" );
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document.write( "Use Pythagoras to find the height:<BR>\n" );
document.write( "8^2 = 5^2 + h^2<BR>\n" );
document.write( "h = sqrt[64-25] = sqrt(39)<BR>\n" );
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document.write( "Area = (1/2)(base)(height)<BR>\n" );
document.write( "= (1/2)(10)*sqrt(39) is approximately 31.22 sq cm<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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