document.write( "Question 687818: x^2+xy+y^2=12
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document.write( "x+y=2\r
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document.write( "solve the following system \n" );
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Algebra.Com's Answer #425356 by lwsshak3(11628) ![]() You can put this solution on YOUR website! x^2+xy+y^2=12 \n" ); document.write( "x+y=2 \n" ); document.write( "solve the following system \n" ); document.write( "x^2+xy+y^2=12 \n" ); document.write( "add xy to both sides \n" ); document.write( "x^2+2xy+y^2=xy+12 \n" ); document.write( "(x+y)^2=xy+12 \n" ); document.write( "From 2nd equation: \n" ); document.write( "(x+y)^2=4=xy+12 \n" ); document.write( "xy=-8 \n" ); document.write( "y=-8/x \n" ); document.write( "x+y=2 \n" ); document.write( "x-8/x=2 \n" ); document.write( "x^2-8=2x \n" ); document.write( "x^2-2x-8=0 \n" ); document.write( "(x-4)(x+2)=0 \n" ); document.write( "x=4 \n" ); document.write( "y=-2 \n" ); document.write( "or \n" ); document.write( "x=-2 \n" ); document.write( "y=4 \n" ); document.write( " \n" ); document.write( " |