document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=61797>Question 61797</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a soil analysis of a lawn determines that 50 pounds of fertilizeer containing 20 % nitrogen is needed. How can this mixture be made from two different fertilizers, one containing 15% nitrogen and the other containing 24% nitrogen? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #42523 by </B><A HREF=/tutors/aboutme.mpl?userid=josmiceli><B>josmiceli(19441)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josmiceli><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=josmiceli><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=42523\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = 15% fertilizer<BR>\n" );
document.write( "y = 24% fertilizer<BR>\n" );
document.write( "x + y = 50<BR>\n" );
document.write( ".15x + .24y = .20*50<BR>\n" );
document.write( ".15x + .24(50 - x) = 10<BR>\n" );
document.write( ".15x + 12 -.24x = 10<BR>\n" );
document.write( "- .09x = -2<BR>\n" );
document.write( "x = 22 2/9 (pounds of 15% fertilizer)<BR>\n" );
document.write( "y = 50 - 22 2/9<BR>\n" );
document.write( "y = 27 7/9 (pounds of 24% fertilizer) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );