document.write( "Question 7705: find a polynomial fuction of the smallest possible degree that will satisfy the following conditions:\r
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document.write( "f(1)=f(3)=f(6)=0 ; f(4)=-12\r
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document.write( "ty \n" );
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Algebra.Com's Answer #4252 by longjonsilver(2297)![]() ![]() You can put this solution on YOUR website! you have 3 roots, at x=1, x=3 and x=6, so we are taking about a cubic, where (x-1)(x-3)(x-6) = 0. The following graph shows just 3 of the possible curves:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the issue is now to find that ONE curve that passes through (4, -12). All the possible curves are just \"multiples\" of y = (x-1)(x-3)(x-6).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "So, we have y = a(x-1)(x-3)(x-6), where a is a constant, so now put in the x and y values.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-12 = a(4-1)(4-3)(4-6) \n" ); document.write( "-12 = a(3)(1)(-2) \n" ); document.write( "-12 = -6a \n" ); document.write( "--> a = 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "so, our required curve is y = 2(x-1)(x-3)(x-6)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "jon. \n" ); document.write( " \n" ); document.write( " |