document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=687441>Question 687441</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find two odd numbers between 30 and 60 such that their ratio is 3:5? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #425157 by </B><A HREF=/tutors/aboutme.mpl?userid=vleith><B>vleith(2983)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=vleith><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=425157\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I am sure there is an algebraic way to solve this. But given the problem, a little logic will help us first.\r<BR>\n" );
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document.write( "You are told the number numbers odd and both be between 30 and 60.<BR>\n" );
document.write( "Their ration is 3:5.\r<BR>\n" );
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document.write( "So first, lets see what numbers between 30 and 60 are odd and divisible by 5.<BR>\n" );
document.write( "There are only 3 numbers that met those conditions -- 35, 45 and 55\r<BR>\n" );
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document.write( "You also know the larger number must be considerably larger than the smaller one. So start with 55. Divide 55 by 5 to get 11. Now multiply 11 by 3 to get 33.\r<BR>\n" );
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document.write( "33 is odd. So 33:55 works.\r<BR>\n" );
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document.write( "Again, you could spend more time settin gup the algebra, but sometimes (like on SAT or GRE) using a different math gets the answer quicker. </SPAN>\n" );
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