document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=687386>Question 687386</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how would you solve this problem using the substitution method for system of equations for this problem 2x-3y=12     x=4y+1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #425140 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=425140\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x-3y=12<BR>\n" );
document.write( "x=4y+1\r<BR>\n" );
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document.write( "substitute x in the first equation\r<BR>\n" );
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document.write( "2(4y+1) -3y=12\r<BR>\n" );
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document.write( "8y+2-3y=12\r<BR>\n" );
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document.write( "5y=12-2<BR>\n" );
document.write( "5y=10<BR>\n" );
document.write( "y=2\r<BR>\n" );
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document.write( "plug y =2 in the second equation\r<BR>\n" );
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document.write( "x=2*4+1\r<BR>\n" );
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document.write( "x=9\r<BR>\n" );
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document.write( "x=9, y=2 </SPAN>\n" );
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