document.write( "Question 687356: How do you write the standard form of an equation of the line that passes through each pair of points? (6,5) (12,-3) \n" ); document.write( "
Algebra.Com's Answer #425138 by mananth(16946)\"\" \"About 
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x1 y1 x2 y2
\n" ); document.write( "6 5 12 -3
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\n" ); document.write( "slope m = (y2-y1)/(x2-x1)
\n" ); document.write( "( -3 - 5 )/( 12 - 6 )
\n" ); document.write( "( -8 / 6 )
\n" ); document.write( "m= -4/3
\n" ); document.write( "The required line passes through both the points. So we select one point and plug it with the slope
\n" ); document.write( "Plug value of the slope and point ( 6 , 5 ) in
\n" ); document.write( "Y = m x + b
\n" ); document.write( "5.00 = -4/3 * 6 + b
\n" ); document.write( "5.00 = -8 + b
\n" ); document.write( "b= 5 + 8
\n" ); document.write( "b= 13
\n" ); document.write( "So the equation will be
\n" ); document.write( "Y = -4/3 x + 13 \r
\n" ); document.write( "\n" ); document.write( "multiply equation by 3\r
\n" ); document.write( "\n" ); document.write( "3y=-4x+39
\n" ); document.write( "4x+3y=39 is the equation
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\n" ); document.write( "m.ananth@hotmail.ca
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