document.write( "Question 61647: 1+cosx/sinx + sinx/1+cosx=4\r
\n" ); document.write( "\n" ); document.write( "csc=sinxtanx + cosx \n" ); document.write( "
Algebra.Com's Answer #42509 by stanbon(75887)\"\" \"About 
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1+cosx/sinx + sinx/1+cosx=4
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\n" ); document.write( "Working with the 1st fraction:
\n" ); document.write( "Multiply numerator and denominator by 1-cosx to get:
\n" ); document.write( "(sinx)^2]/[sinx(1-cosx)]
\n" ); document.write( "=sinx/(1-cosx)
\n" ); document.write( "Rewriting the problem you get:
\n" ); document.write( "sinx/(1-cosx) + sinx/(1+cosx) = 4
\n" ); document.write( "Multiply thru by (1-cosx)(1+cosx) which happens to be (sinx)^2 you get:
\n" ); document.write( "sinx(1+cosx) + sinx(1-cosx)=4(sinx)^2
\n" ); document.write( "2sinx =4(sinx)^2
\n" ); document.write( "1=2sinx
\n" ); document.write( "sinx=1/2
\n" ); document.write( "x=30 degrees.
\n" ); document.write( "-----------------
\n" ); document.write( "csc=sinxtanx + cosx
\n" ); document.write( "(1/sinx) = (sinx)^2/cosx + cosx
\n" ); document.write( "Multiply thru by sinx(cosx) to get:
\n" ); document.write( "cosx = (sinx)^3 + sinx(cosx)^2
\n" ); document.write( "cosx = (sinx)[(sinx)^2+(cosx)^2)
\n" ); document.write( "cosx = sinx
\n" ); document.write( "tanx = 1
\n" ); document.write( "x=45 degrees
\n" ); document.write( "--------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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