document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=61770>Question 61770</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 5x+2x-9=40            we just need to solve the problem. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #42507 by </B><A HREF=/tutors/aboutme.mpl?userid=jai_kos><B>jai_kos(139)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jai_kos><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=42507\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given 5x + 2x - 9 = 40 <BR>\n" );
document.write( "Group up all the \"x\" terms in one side and all the numbers on the other side,<BR>\n" );
document.write( "We get<BR>\n" );
document.write( "5x +2x = 40 + 9<BR>\n" );
document.write( "7x = 49<BR>\n" );
document.write( "Divide by 7 on both sides, we get<BR>\n" );
document.write( "x = 49 / 7<BR>\n" );
document.write( "x = 7<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );