document.write( "Question 686364: e=square root of 5/2 ; major axis along the x-axis ; minor axis along the line x-5=0 ; passes through the point 5,2 \n" ); document.write( "
Algebra.Com's Answer #425053 by lwsshak3(11628)\"\" \"About 
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e=square root of 5/2 ; major axis along the x-axis ; minor axis along the line x-5=0 ; passes through the point 5,2
\n" ); document.write( "I will assume e=sqrt of 2/5 instead of 5/2 (0 < e < 1 for ellipses)
\n" ); document.write( "**
\n" ); document.write( "This is an ellipse with horizontal major axis.
\n" ); document.write( "Its standard form of equation:
\n" ); document.write( "\"%28x-h%29%5E2%2Fa%5E2%2B%28y-k%29%5E2%2Fb%5E2=1\", a>b, (h,k)=(x,y) coordinates of center
\n" ); document.write( "For given ellipse:
\n" ); document.write( "center: (5,0)
\n" ); document.write( "plug in coordinates of center and given point (5,2)
\n" ); document.write( "(5-5)^2/a^2+(2-0)^2/b^2=1
\n" ); document.write( "4/b^2=1
\n" ); document.write( "b^2=4
\n" ); document.write( "..
\n" ); document.write( "eccentricity=√(2/5)=√(a^2-b^2)/a
\n" ); document.write( "square both sides
\n" ); document.write( "2/5=(a^2-b^2)/a^2
\n" ); document.write( "2a^2=5a^2-5b^2
\n" ); document.write( "3a^2=5b^2
\n" ); document.write( "a^2=5b^2/3
\n" ); document.write( "a^2=20/3\r
\n" ); document.write( "\n" ); document.write( "..
\n" ); document.write( "Equation:
\n" ); document.write( "\"3%28x-5%29%5E2%2F20%2By%5E2%2F4=1\" \r
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