document.write( "Question 687136: 2w^2+13w+20 I need help I don't know how to factor this \n" ); document.write( "
Algebra.Com's Answer #425049 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Looking at the expression \"2w%5E2%2B13w%2B20\", we can see that the first coefficient is \"2\", the second coefficient is \"13\", and the last term is \"20\".\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient \"2\" by the last term \"20\" to get \"%282%29%2820%29=40\".\r
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\n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to \"40\" (the previous product) and add to the second coefficient \"13\"?\r
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\n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of \"40\" (the previous product).\r
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\n" ); document.write( "\n" ); document.write( "Factors of \"40\":\r
\n" ); document.write( "\n" ); document.write( "1,2,4,5,8,10,20,40\r
\n" ); document.write( "\n" ); document.write( "-1,-2,-4,-5,-8,-10,-20,-40\r
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\n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to \"40\".\r
\n" ); document.write( "\n" ); document.write( "1*40 = 40
\n" ); document.write( "2*20 = 40
\n" ); document.write( "4*10 = 40
\n" ); document.write( "5*8 = 40
\n" ); document.write( "(-1)*(-40) = 40
\n" ); document.write( "(-2)*(-20) = 40
\n" ); document.write( "(-4)*(-10) = 40
\n" ); document.write( "(-5)*(-8) = 40\r
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\n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient \"13\":\r
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First NumberSecond NumberSum
1401+40=41
2202+20=22
4104+10=14
585+8=13
-1-40-1+(-40)=-41
-2-20-2+(-20)=-22
-4-10-4+(-10)=-14
-5-8-5+(-8)=-13
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\n" ); document.write( "\n" ); document.write( "From the table, we can see that the two numbers \"5\" and \"8\" add to \"13\" (the middle coefficient).\r
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\n" ); document.write( "\n" ); document.write( "So the two numbers \"5\" and \"8\" both multiply to \"40\" and add to \"13\"\r
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\n" ); document.write( "\n" ); document.write( "Now replace the middle term \"13w\" with \"5w%2B8w\". Remember, \"5\" and \"8\" add to \"13\". So this shows us that \"5w%2B8w=13w\".\r
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\n" ); document.write( "\n" ); document.write( "\"2w%5E2%2Bhighlight%285w%2B8w%29%2B20\" Replace the second term \"13w\" with \"5w%2B8w\".\r
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\n" ); document.write( "\n" ); document.write( "\"%282w%5E2%2B5w%29%2B%288w%2B20%29\" Group the terms into two pairs.\r
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\n" ); document.write( "\n" ); document.write( "\"w%282w%2B5%29%2B%288w%2B20%29\" Factor out the GCF \"w\" from the first group.\r
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\n" ); document.write( "\n" ); document.write( "\"w%282w%2B5%29%2B4%282w%2B5%29\" Factor out \"4\" from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.\r
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\n" ); document.write( "\n" ); document.write( "\"%28w%2B4%29%282w%2B5%29\" Combine like terms. Or factor out the common term \"2w%2B5\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"2w%5E2%2B13w%2B20\" factors to \"%28w%2B4%29%282w%2B5%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"2w%5E2%2B13w%2B20=%28w%2B4%29%282w%2B5%29\".\r
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\n" ); document.write( "\n" ); document.write( "Note: you can check the answer by expanding \"%28w%2B4%29%282w%2B5%29\" to get \"2w%5E2%2B13w%2B20\" or by graphing the original expression and the answer (the two graphs should be identical).
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