document.write( "Question 687037: how can I factor by grouping this problem.
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Algebra.Com's Answer #425022 by josh_jordan(263)\"\" \"About 
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To factor by grouping, you want to find similar terms. With \"3a%5E3%2B2a%5E2%2B6a%2B4\", the easiest way to group is by looking at the numbers in front of the variables and seeing if any of the numbers are factors of each other. 3 and 6 are factors of 6, and 2 and 4 are factors of 4. So, let's try grouping 3a^3 and 6a together, and 2a^2 and 4 together:\r
\n" ); document.write( "\n" ); document.write( "\"%283a%5E3%2B6a%29%2B%282a%5E2%2B4%29\"\r
\n" ); document.write( "\n" ); document.write( "In the first set of parenthesis, we can factor out 3a:\r
\n" ); document.write( "\n" ); document.write( "\"3a%28a%5E2%2B2%29\"\r
\n" ); document.write( "\n" ); document.write( "In the second set of parenthesis, we can factor out a 2:\r
\n" ); document.write( "\n" ); document.write( "\"2%28a%5E2%2B2%29\"\r
\n" ); document.write( "\n" ); document.write( "Putting these both together, results in:\r
\n" ); document.write( "\n" ); document.write( "\"3a%28a%5E2%2B2%29%2B2%28a%5E2%2B2%29\"\r
\n" ); document.write( "\n" ); document.write( "As you can see, there are two sets of \"%28a%5E2%2B2%29\"\r
\n" ); document.write( "\n" ); document.write( "We can group these together, and then, in another set of parenthesis, group the remaining terms together:\r
\n" ); document.write( "\n" ); document.write( "\"%283a%2B2%29%28a%5E2%2B2%29\", which is our final answer
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