document.write( "Question 61760: Can anyone help me out with this? I have submitted once before but didn't get a response. I am really stuck with this one. Thanks!\r
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\n" ); document.write( "\n" ); document.write( "|2/3x-1|>5 solve for x\r
\n" ); document.write( "\n" ); document.write( "the marks on the left of 2/3x is an absolute value sign. The mark on the right of 1 is as well. I hope that is clear enough. Thanks again! \n" ); document.write( "
Algebra.Com's Answer #42502 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
|2/3x-1|>5 solve for x
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\n" ); document.write( "We don't know if (2/3)x-1 is negative or not negative
\n" ); document.write( "so we have to check both possibilities:
\n" ); document.write( "Checking that it is positive you get:
\n" ); document.write( "(2/3)x-1>5
\n" ); document.write( "(2/3)x>6
\n" ); document.write( "x>9
\n" ); document.write( "-------------
\n" ); document.write( "Checking that it is negative:
\n" ); document.write( "-((2/3)x-1)>5
\n" ); document.write( "(2/3)x-1<-5
\n" ); document.write( "(2/3)x<-4
\n" ); document.write( "x<-6
\n" ); document.write( "-------------
\n" ); document.write( "Solution:
\n" ); document.write( "x<-6 or x>9
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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