document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1376>Question 1376</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Antoine rode his bike the 4 miles to the fair at a relaxed pace. He stayed to long and had to double his speed on the way back in order to get home in time for dinner. If his total time traveling was 3 hours, how fast did he travel in each direction?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #425 by </B><A HREF=/tutors/aboutme.mpl?userid=khwang><B>khwang(438)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=khwang><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=425\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let V be the speed of his going to the fair, then his speed of the return trip<BR>\n" );
document.write( " was 2V.<BR>\n" );
document.write( " Now the total distance of the round trip is 2*4 = 8 miles.\r<BR>\n" );
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document.write( " By Speed = Distance / Time , and so  Time =  Distance /SPeed,<BR>\n" );
document.write( " we have 3 = 8/V + 8/(2V),<BR>\n" );
document.write( " Cancel the denominator by multiple by 2, 6V = 16 + 8 = 24.<BR>\n" );
document.write( " so, V =4 and 2V = 8.\r<BR>\n" );
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document.write( " Hence, his speed going to the fair was 4 miles/hr,and <BR>\n" );
document.write( " his speed backing home was 8 miles/hr. </SPAN>\n" );
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