document.write( "Question 686974: I don't understand how to find the factors for this equation : 4x to the second power + 10x + 4=\r
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document.write( "The answer is 2(2x to the second power + 5x + 2)
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document.write( " = 2(2x + 1)(x+2)\r
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document.write( "I understand the first problem, but I don't see the 10x in the final solution. I don't understand why this is the answer.
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Algebra.Com's Answer #424985 by Stitch(470)![]() ![]() ![]() You can put this solution on YOUR website! Given: \n" ); document.write( "\n" ); document.write( "If you factor a 2 out of each number, the equation can be written as: \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You need to remember to multiply the equation by 2 later but lets just look at the \n" ); document.write( "\n" ); document.write( "Find the factors of the last 2 in the equation: 1 & 2 \n" ); document.write( "Find the factors of 2X^2: 1X & 2X \n" ); document.write( "Now since the last 2 is positive that means that both factors contain both + signs or both - signs. \n" ); document.write( "But since the 5X is positive, both factors can not contain negative signs. \n" ); document.write( "Then you have to see which of your factors fit. \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now we have to multiply that equation by 2 since we divided it by 2 in the first place. \n" ); document.write( " \n" ); document.write( "------------------------------------------\r \n" ); document.write( "\n" ); document.write( "You can always double check your answer by goin backwards and making sure you get what you started with. \n" ); document.write( "Use the foil method on the inside of the parentheses. \n" ); document.write( "(FOIL = first, outer, inner last)\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "Simplify \n" ); document.write( " \n" ); document.write( "Combine like terms \n" ); document.write( " \n" ); document.write( "Now multiply that by the 2 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |