document.write( "Question 686696: I am not understanding how to start this word problem. We are supposed to be using quadratic equations. The problem is.....
\n" ); document.write( "
\n" ); document.write( " The length of a rectangle is 1cm more than twice it's width and 2cm less than the length of the diagonal of the rectangle. Find the dimensions of the rectangle.\r
\n" ); document.write( "\n" ); document.write( "I think the diagonal part is confusing me because we have never solved a problem with diagonal before.
\n" ); document.write( "

Algebra.Com's Answer #424878 by lwsshak3(11628)\"\" \"About 
You can put this solution on YOUR website!
The length of a rectangle is 1cm more than twice it's width and 2cm less than the length of the diagonal of the rectangle. Find the dimensions of the rectangle.
\n" ); document.write( "**
\n" ); document.write( "let x=width
\n" ); document.write( "length=2x+1
\n" ); document.write( "diagonal=√(width^2+length^2) (by the pythagorean theorem)
\n" ); document.write( "=√[(x^2+(2x+1)^2]
\n" ); document.write( "=√[x^2+4x^2+4x+1]
\n" ); document.write( "=√(5x^2+4x+1)
\n" ); document.write( "..
\n" ); document.write( "(2x+1)+2=diagonal
\n" ); document.write( "2x+3=√(5x^2+4x+1)
\n" ); document.write( "square both sides
\n" ); document.write( "4x^2+12x+9=5x^2+4x+1
\n" ); document.write( "x^2-8x-8=0
\n" ); document.write( "solve for x by following quadratic formula:
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "a=1, b=-8, c=-8
\n" ); document.write( "ans:
\n" ); document.write( "x≈8.9
\n" ); document.write( "2x+1≈18.8
\n" ); document.write( "width≈8.9 cm
\n" ); document.write( "length≈18.8 cm
\n" ); document.write( "
\n" );