document.write( "Question 686696: I am not understanding how to start this word problem. We are supposed to be using quadratic equations. The problem is.....
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document.write( " The length of a rectangle is 1cm more than twice it's width and 2cm less than the length of the diagonal of the rectangle. Find the dimensions of the rectangle.\r
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document.write( "I think the diagonal part is confusing me because we have never solved a problem with diagonal before. \n" );
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Algebra.Com's Answer #424878 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! The length of a rectangle is 1cm more than twice it's width and 2cm less than the length of the diagonal of the rectangle. Find the dimensions of the rectangle. \n" ); document.write( "** \n" ); document.write( "let x=width \n" ); document.write( "length=2x+1 \n" ); document.write( "diagonal=√(width^2+length^2) (by the pythagorean theorem) \n" ); document.write( "=√[(x^2+(2x+1)^2] \n" ); document.write( "=√[x^2+4x^2+4x+1] \n" ); document.write( "=√(5x^2+4x+1) \n" ); document.write( ".. \n" ); document.write( "(2x+1)+2=diagonal \n" ); document.write( "2x+3=√(5x^2+4x+1) \n" ); document.write( "square both sides \n" ); document.write( "4x^2+12x+9=5x^2+4x+1 \n" ); document.write( "x^2-8x-8=0 \n" ); document.write( "solve for x by following quadratic formula: \n" ); document.write( " \n" ); document.write( "a=1, b=-8, c=-8 \n" ); document.write( "ans: \n" ); document.write( "x≈8.9 \n" ); document.write( "2x+1≈18.8 \n" ); document.write( "width≈8.9 cm \n" ); document.write( "length≈18.8 cm \n" ); document.write( " |