document.write( "Question 61696This question is from textbook Alegbra Concepts and Applications
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document.write( ": Use substitution to solve for x and y\r
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document.write( "4x - y = -7\r
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document.write( "2x + 2y = 4 \n" );
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Algebra.Com's Answer #42485 by jai_kos(139)![]() ![]() ![]() You can put this solution on YOUR website! Given 4x - y = -7 --->(1) \n" ); document.write( " 2x + 2y = 4 --->(2) \n" ); document.write( "Divide equation(2) by 2, we get \n" ); document.write( "x + y = 2 \n" ); document.write( "x = 2 - y --->(3) \n" ); document.write( "Substitue the equation(3) in equation(1), we get... \n" ); document.write( "4(2-y) -y = -7 \n" ); document.write( "8 - 4y -y = -7 \n" ); document.write( "8 -5y = -7 \n" ); document.write( "-5y = - 7 - 8 \n" ); document.write( "-5y = -15 \n" ); document.write( "y = -15/ - 5 \n" ); document.write( "y = 3 --->(4) \n" ); document.write( "Now substitue the value of y =3 in eqution(3), we get \n" ); document.write( "x = 2 - 3 = -1 \n" ); document.write( "x =-1 \n" ); document.write( "Therefore we have the x =-1 and y = 3 \n" ); document.write( " \n" ); document.write( " |