document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=686181>Question 686181</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the trigonometric value of angle &#1256;.\r<BR>\n" );
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document.write( "sec &#1256;=(5/2) and &#1256; in quadrant IV.\r<BR>\n" );
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document.write( "Thank you for help in advance, the quadrant portion is mainly throwing me off so help is appreciated. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #424811 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=424811\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the trigonometric value of angle &#1256;. <BR>\n" );
document.write( "sec &#1256;=(5/2) and &#1256; in quadrant IV.<BR>\n" );
document.write( "cos &#1256;=1/sec &#1256;=2/5<BR>\n" );
document.write( "using calculator and cos inverse function key:<BR>\n" );
document.write( "cos &#1256;^-1(2/5)=293.58º or 5.12 radians in quadrant IV where cos>0<BR>\n" );
document.write( "&#1256; would be 66.42º or 1.56 radians in quadrant I where also cos>0 </SPAN>\n" );
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