document.write( "Question 686336: Solve the equation on the interval [0,2π), tan(x)sec(x) = 3tan(x)
\n" ); document.write( "Round your answer to the nearest fourth decimal place.
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Algebra.Com's Answer #424797 by lwsshak3(11628)\"\" \"About 
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Solve the equation on the interval [0,2π), tan(x)sec(x) = 3tan(x)
\n" ); document.write( "Round your answer to the nearest fourth decimal place.
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\n" ); document.write( "tan(x)sec(x) = 3tan(x)
\n" ); document.write( "3tanx-tan(x)sec(x)=0
\n" ); document.write( "tanx(3-secx)=0
\n" ); document.write( "tanx=0
\n" ); document.write( "x=0, π)
\n" ); document.write( "or
\n" ); document.write( "3-secx=0
\n" ); document.write( "secx=3
\n" ); document.write( "cosx=1/3
\n" ); document.write( "x≈1.2310, 5.0552
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