document.write( "Question 686438: Working together, Linda and Kathy can
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Algebra.Com's Answer #424784 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
>>Working together, Linda and Kathy can clean a beach house in 5.14 hours.<<
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document.write( "So, their rate working together is 1 house per 5.14 hours or \r\n" );
document.write( "\"%281house%29%2F%285.14hours%29\" or \"1%2F5.14\"\"house%2Fhours\"\r\n" );
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\n" ); document.write( ">>Had she done it alone it would have taken Linda 11 hours.<<
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document.write( "So, Linda's rate working alone is 1 house per 11 hours or \r\n" );
document.write( "\"%281house%29%2F%2811hours%29\" or \"1%2F11\"\"house%2Fhours\"\r\n" );
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\n" ); document.write( ">>How long would it take Kathy to do it alone?<<
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document.write( "Suppose it would take Kathy x hours to do it alone.\r\n" );
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document.write( "So, Kathy's rate working alone is 1 house per x hours or \r\n" );
document.write( "\"%281house%29%2F%28x_hours%29\" or \"1%2Fx\"\"house%2Fhours\"\r\n" );
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document.write( "The equation comes from:\r\n" );
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document.write( "                            \"1%2F11\" + \"1%2Fx\" = \"1%2F5.14\"\r\n" );
document.write( "Eliminate the decimal by multiplying top and bottom of the last fraction\r\n" );
document.write( "by 100\r\n" );
document.write( "                            \"1%2F11\" + \"1%2Fx\" = \"100%2F514\"\r\n" );
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document.write( "Multiply through by 5654x\r\n" );
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document.write( "                       514x + 5654 = 1100x\r\n" );
document.write( "                              5654 = 586x\r\n" );
document.write( "                               \"5654%2F586\" = x\r\n" );
document.write( "                               \"2827%2F293\" = x\r\n" );
document.write( "                       9.648464164 = x\r\n" );
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document.write( "Round off to hundredths 9.65 hours.\r\n" );
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document.write( "Edwin

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