document.write( "Question 686444: log(3x+7)+log(x-2)=1 \n" ); document.write( "
Algebra.Com's Answer #424770 by lynnlo(4176)![]() ![]() ![]() You can put this solution on YOUR website! log(3x+7)+log(x-2)=1 \n" ); document.write( "log(3x+7)*(x-2)=1 \n" ); document.write( "(3x+7)(x-2)=10 \n" ); document.write( "3x^2-6x+7x-14-10=0 \n" ); document.write( "3x^2+x-24=0 \n" ); document.write( "3x^2+9x-8x-24=0 \n" ); document.write( "3x(x+3)-8(x+3)=0 \n" ); document.write( "(3x-8)(x+3)=0 \n" ); document.write( "3x-8=0 OR x=8/3 \n" ); document.write( "x=8/3 \n" ); document.write( " |