document.write( "Question 686444: log(3x+7)+log(x-2)=1 \n" ); document.write( "
Algebra.Com's Answer #424770 by lynnlo(4176)\"\" \"About 
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log(3x+7)+log(x-2)=1
\n" ); document.write( "log(3x+7)*(x-2)=1
\n" ); document.write( "(3x+7)(x-2)=10
\n" ); document.write( "3x^2-6x+7x-14-10=0
\n" ); document.write( "3x^2+x-24=0
\n" ); document.write( "3x^2+9x-8x-24=0
\n" ); document.write( "3x(x+3)-8(x+3)=0
\n" ); document.write( "(3x-8)(x+3)=0
\n" ); document.write( "3x-8=0 OR x=8/3
\n" ); document.write( "x=8/3
\n" ); document.write( "
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