document.write( "Question 61685: ABCD is a square. Point A has co-ordinates (2,4) and the line ODC has equation y=x.
\n" ); document.write( "find the equation of line AD
\n" ); document.write( "find the co-ordinates of point D
\n" ); document.write( "find the area of square ABCD \n" ); document.write( "
Algebra.Com's Answer #42476 by venugopalramana(3286)\"\" \"About 
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ABCD is a square. Point A has co-ordinates (2,4) and the line ODC has equation y=x.
\n" ); document.write( "find the equation of line AD
\n" ); document.write( "find the co-ordinates of point D
\n" ); document.write( "find the area of square ABCD
\n" ); document.write( "AD IS PERPENDICULAR TO ODC .HENCE ITS SLOPE IS -1
\n" ); document.write( "ITS EQN.IS
\n" ); document.write( "Y-4 = -1(X-2)
\n" ); document.write( "Y+X=6....IS THE EQN.OF AD.
\n" ); document.write( "SINCE D IS ON Y=X,ITS COORDINATES WILL BE (H,H) SAY
\n" ); document.write( "BUT IT IS ALSO ON AD .
\n" ); document.write( "HENCE IT WILL SATISFY EQN OF AD ..Y+X=6
\n" ); document.write( "H+H=6....H=3
\n" ); document.write( "COORDINATES OF D ARE (3,3)
\n" ); document.write( "SIDE OF SQUARE = AD = SQRT[(3-2)^2+(3-4)^2]=SQRT(2)
\n" ); document.write( "AREA OF SQUARE = [SQRT(2)]^2= 2 SQ.UNITS.
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