document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=686264>Question 686264</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a ladder 20 feet long rests 12 feet from the base of a sloping wall and reaches 14 feet up the face of the wall. What is the angle of inclation of the ladder of the wall?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #424733 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=424733\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a ladder 20 feet long rests 12 feet from the base of a sloping wall and reaches 14 feet up the face of the wall. What is the angle of inclation of the ladder of the wall?<BR>\n" );
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document.write( "since you know the \"adjacent\" and \"opposite\" sides of the triangle, we can use the trigonometric relation of:<BR>\n" );
document.write( "tan x = oppo/adjacent<BR>\n" );
document.write( "tan x = 14/20<BR>\n" );
document.write( "tan x = 7/10<BR>\n" );
document.write( "x = arctan(7/10)<BR>\n" );
document.write( "x = 35 degrees\r<BR>\n" );
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