document.write( "Question 686184: Determine the vertex, focus and directrix of the parabola: \r
\n" );
document.write( "
\n" );
document.write( "\n" );
document.write( "y^2-6x-8x=-17 \n" );
document.write( "
Algebra.Com's Answer #424729 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Determine the vertex, focus and directrix of the parabola: \n" ); document.write( "y^2-6x-8x=-17 \n" ); document.write( "y^2-14x=-17 \n" ); document.write( "y^2=14x-17 \n" ); document.write( "y^2=14(x-17/14) \n" ); document.write( "This is a parabola that opens rightwards. \n" ); document.write( "Its standard form of equation: (y-k)^2=4p(x-h), (h,k)=(x,y) coordinates of the vertex \n" ); document.write( "For given parabola: \n" ); document.write( "vertex: (17/14,0) \n" ); document.write( "axis of symmetry: y=0 or x-axis \n" ); document.write( "4p=14 \n" ); document.write( "p=14/4=7/2=49/14 \n" ); document.write( "focus: (66/14,0) (p distance to the right of vertex on the axis of symmetry) \n" ); document.write( "directrix: y=-32/14 (p distance to the left of vertex on the axis of symmetry) \n" ); document.write( " |