document.write( "Question 686184: Determine the vertex, focus and directrix of the parabola: \r
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\n" ); document.write( "\n" ); document.write( "y^2-6x-8x=-17
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Algebra.Com's Answer #424729 by lwsshak3(11628)\"\" \"About 
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Determine the vertex, focus and directrix of the parabola:
\n" ); document.write( "y^2-6x-8x=-17
\n" ); document.write( "y^2-14x=-17
\n" ); document.write( "y^2=14x-17
\n" ); document.write( "y^2=14(x-17/14)
\n" ); document.write( "This is a parabola that opens rightwards.
\n" ); document.write( "Its standard form of equation: (y-k)^2=4p(x-h), (h,k)=(x,y) coordinates of the vertex
\n" ); document.write( "For given parabola:
\n" ); document.write( "vertex: (17/14,0)
\n" ); document.write( "axis of symmetry: y=0 or x-axis
\n" ); document.write( "4p=14
\n" ); document.write( "p=14/4=7/2=49/14
\n" ); document.write( "focus: (66/14,0) (p distance to the right of vertex on the axis of symmetry)
\n" ); document.write( "directrix: y=-32/14 (p distance to the left of vertex on the axis of symmetry)
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