document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=686127>Question 686127</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do you work this problem?\r<BR>\n" );
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document.write( "1/6(a-4)=1/3(2a+4) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #424702 by </B><A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><B>ReadingBoosters(3246)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ReadingBoosters><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=424702\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1/6(a-4)=1/3(2a+4)<BR>\n" );
document.write( "You could either distribute the 1/6 and the 1/3 or <BR>\n" );
document.write( "multiply the entire equation by 18 (LCM of 6 and 3) to remove the fractions.<BR>\n" );
document.write( "...<BR>\n" );
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document.write( "3(a-4) = 6(2a+4) ==> distribute the 3 and 6<BR>\n" );
document.write( "3a - 12 = 12a + 24 ==> group like terms<BR>\n" );
document.write( "3a - 12a = 24 + 12 ==> combine like terms<BR>\n" );
document.write( "-9a = 36 ==> divide both sides by -9 to isolate the a variable<BR>\n" );
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