document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=7680>Question 7680</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the answer for this linear equation 10n+12=14n-12 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #4247 by </B><A HREF=/tutors/aboutme.mpl?userid=drglass><B>drglass(89)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drglass><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=4247\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In a problem like this, you want to isolate the variable from the constants. This means, you want the <i>n</i> on one side and the numbers on the other. You can to this as follows:\r<BR>\n" );
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document.write( "subtract 10n from both sides to get<BR>\n" );
document.write( "10n + 12 - 10n = 14n - 12 - 10n, rearrange the terms to get<BR>\n" );
document.write( "10n - 10n + 12 = 14n - 10n - 12, or<BR>\n" );
document.write( "0 + 12 = 4n - 12\r<BR>\n" );
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document.write( "Now, add 12 to both sides<BR>\n" );
document.write( "12 + 12 = 4n - 12 + 12 or<BR>\n" );
document.write( "24 = 4n\r<BR>\n" );
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document.write( "Divide both sides by 4 to get<BR>\n" );
document.write( "24/4 = 4n/4 or<BR>\n" );
document.write( "6 = n.\r<BR>\n" );
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document.write( "You can check this by replacing n with 6 in the original equation.\r<BR>\n" );
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document.write( "10(6) + 12 = 14(6) - 12<BR>\n" );
document.write( "60 + 12 = 84 - 12<BR>\n" );
document.write( "72 = 72\r<BR>\n" );
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document.write( "This is true, so n = 6 is correct  </SPAN>\n" );
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