document.write( "Question 686003: use the quadratic formula to solve x2 -10x +25 = 12 \n" ); document.write( "
Algebra.Com's Answer #424682 by ReadingBoosters(3246)\"\" \"About 
You can put this solution on YOUR website!
Step One: set the equation equal to 0
\n" ); document.write( "\"x%5E2-10x+%2B+25+-+12+=+0\"
\n" ); document.write( "so,
\n" ); document.write( "\"x%5E2+-+10x+%2B+13+=+0\"
\n" ); document.write( "apply the quadratic formula \"x=%28-b%2B-sqrt%28b%5E2-4%28a%29%28c%29%29%29%2F%282%2Aa%29\"
\n" ); document.write( "compare to the standard equation ax^2 + bx + c = 0 and
\n" ); document.write( "a = 1, b = -10 and c = 13
\n" ); document.write( "therefore,
\n" ); document.write( "\"x+=+%28-%28-10%29%2B-sqrt%28%28-10%29%5E2-4%281%29%2813%29%29%29%2F%282%2A1%29\"
\n" ); document.write( "...
\n" ); document.write( "\"x+=+%2810%2B-sqrt%28100-52%29%29%2F2\"
\n" ); document.write( "...
\n" ); document.write( "\"x+=+%2810%2B-sqrt%2848%29%29%2F2\" where \"sqrt%2848%29+=+sqrt%2816%2A3%29+=+4sqrt%283%29\"
\n" ); document.write( "...
\n" ); document.write( "\"x+=+%2810%2B-4sqrt%283%29%29%2F2\"
\n" ); document.write( "...
\n" ); document.write( "\"x+=+10%2F2+%2B-+4sqrt%283%29%2F2\"
\n" ); document.write( "...
\n" ); document.write( "\"x+=+5+%2B-+2sqrt%283%29\"
\n" ); document.write( "ultimately
\n" ); document.write( "\"highlight_green%28x+=+5+%2B+2sqrt%283%29%29\"
\n" ); document.write( "AND
\n" ); document.write( "\"highlight_green%28x+=+5+-+2sqrt%283%29%29\"
\n" ); document.write( "..............................
\n" ); document.write( "Have more questions?
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