document.write( "Question 685877: Change the formula to make B the subjct\r
\n" ); document.write( "\n" ); document.write( "A= b(b+2BL) when A = 1024 and L = 60\r
\n" ); document.write( "\n" ); document.write( "I have tried rearranging it but I always seem to end with B on both sides..which I know isn't correct. I know B must be able to be made the subject as I've found B to be worth 8 by changing the formula so it can be worked via a quadratic equation. I just cannot fathom out how to make B the subject. Thanks
\n" ); document.write( "

Algebra.Com's Answer #424626 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
I guess you have all b's small letters here:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"A=+b%28b%2B2bL%29\" \r
\n" ); document.write( "\n" ); document.write( "\"A=+b%2Ab%281%2B2L%29\"\r
\n" ); document.write( "\n" ); document.write( "\"A=+b%5E2%281%2B2L%29\"\r
\n" ); document.write( "\n" ); document.write( "\"A%2F%281%2B2L+%29=+b%5E2\"..........when \"A+=+1024\" and \"L+=+60\" \r
\n" ); document.write( "\n" ); document.write( "\"1024%2F%281%2B2%2A60+%29=+b%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"1024%2F121=+b%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"8.46=+b%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"b=sqrt%288.46%29\"\r
\n" ); document.write( "\n" ); document.write( "\"b=2.91\"
\n" ); document.write( "
\n" ); document.write( "
\n" );