document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=685863>Question 685863</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cars leave towns 640 kilometers apart at the same time and travel toward each other. One car's rate is 10 kilometers per hour more than the other's. If they meet in 4 hours, what is the rate of the faster car?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #424612 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=424612\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Two cars leave towns 640 kilometers apart at the same time and travel toward each other. One car's rate is 10 kilometers per hour more than the other's. If they meet in 4 hours, what is the rate of the faster car?<BR>\n" );
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document.write( "let x=rate of speed of faster car<BR>\n" );
document.write( "x-10=rate of speed of slower  car<BR>\n" );
document.write( "distance=rate of speed*travel time<BR>\n" );
document.write( "4x+4(x-10)=640<BR>\n" );
document.write( "4x+4x-40=640<BR>\n" );
document.write( "8x=680<BR>\n" );
document.write( "x=85<BR>\n" );
document.write( "rate of speed of faster car= 85km/hr </SPAN>\n" );
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