document.write( "Question 685734: A and B working together can finish a certain job in 20/3 hours. They start the work together but after 3 hours, A became ill and B continuing the work alone finished it in 33/4 hours. How long would it take each working alone to do the job. \n" ); document.write( "
Algebra.Com's Answer #424553 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A and B working together can finish a certain job in 20/3 hours. They start the work together but after 3 hours, A became ill and B continuing the work alone finished it in 33/4 hours. How long would it take each working alone to do the job. \n" ); document.write( "--- \n" ); document.write( "Let a and b be their respective rates: \n" ); document.write( "Equations: \n" ); document.write( "a + b = (3/20) job/hr \n" ); document.write( "3a + (3+(33/4))b = 1 job/hr \n" ); document.write( "--------------------------------- \n" ); document.write( "Rearrange: \n" ); document.write( "3a + 3b = (9/20) \n" ); document.write( "3a + (45/4)b = 1 \n" ); document.write( "--- \n" ); document.write( "Subtract and solve for \"b\": \n" ); document.write( "(33/4)b = 11/20 \n" ); document.write( "b = (11/20)(4/33) = (1/15) \n" ); document.write( "B would take 15 hours to do the job alone \n" ); document.write( "------ \n" ); document.write( "Solve for \"a\" using a + b = 3/20 \n" ); document.write( "a + 1/15 = 3/20 \n" ); document.write( "-- \n" ); document.write( "a = (3/20)-(1/15) \n" ); document.write( "a = (9-4)/60 = 1/12 \n" ); document.write( "--- \n" ); document.write( "A would take 12 hours to do the job alone \n" ); document.write( "============================================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |